 CHM1022 Lab Report 1

Level Law of an Iodine Time Reaction

Name: Sashini Naomi Wijesekera

Scholar ID: 23877847

Lab Partner: Zahiya Vorbeter

Lab Period: Monday on the lookout for. 00am

Goal

The aim of the experiment is always to determine the factors that affect the level of a reaction, by performing the iodine clock response and repeating it changing different primary conditions in order to measure and compare the speed of response for each research and experimentally determine the rate law.

Method

Refer CHM1022 Laboratory Manual, Semester you 2013.

Benefits and Calculations-

Part A- Calculations of rate for starters set of conditions

1 . n(S2O32-)=CV

=0. 0025M*(10/1000)L

=2. 50*10-5mol

Molar ratio of I2: S2O32- = 1: 2

n(I2)=0. 5*n(S2O32-)

=0. 5*(2. 50*10-5mol)

=1. 25*10-5mol

Mean time taken for blue colour to appear sama dengan (131sec+135sec+145sec)/3 =137seconds

Rate of reaction=n(I2)/t

=(1. 25*10-5mol/137sec)

=9. 12*10-8mols-1

[H2O2]: C1V1=C2V2

0. 8*1=C2*99

C2=8. 08*10-3M

[I-]: C1V1= C2V2

0. 025*10=C2*99

C2=2. 53*10-3M

[H30+]: C1V1= C2V2

0. 36*35=C2*99

C2=0. 127M

[S2O32-]: C1V1= C2V2

0. 0025*10=C2*99

C2=2. 53*10-4M

Part B-Results and measurements

B4 (i)

n(S2O32-) = 0. 0025*(5/1000)

sama dengan 1 . 25*10-5mol

Molar proportion of I2: S2O32-=1: two

n(I2)=0. 5*n(S2O32-)

n(I2)= 0. 5*(1. 25*10-5)

=6. 25*10-6mol

B4 (ii)

n(S2O32-)= 0. 0025*(20/1000)

= 5*10-5mol

Gustar ratio ofI2: S2O32-=1: 2

n(I2)=0. 5*n(S2O32-)

n(I2)=0. 5*(5. 0*10-5)

=2. 5*10-5mol

Part B-Results and calculations

| | | | | | | |Time/s |n(I2)/mol |Rate/mol s-1 |Concentration/M | | | | | | | | | | | | | | | | | | | | | | | |

|1 |2 |3 |4 |5 |6 |Mean time/s | | | | |B1[H202]

(i)higher

(ii)lower

66

63

61

67

69

60

64

1 . 25*10-5

(1. 25*10-5)/64=1. 95*10-7 |[H2O2]:

C1V1= C2V2

0. 8*2=C2*99

C2=0. 016 | |

249

287

242

262

252

260

259

1 ) 25*10-5

(1. 25*10-5)/259=4. 83*10-8 |[H2O2]:

C1V1= C2V2

zero. 8*0. 5=C2*99

C2=4. 0*10-3 | |B2[I-]

(i)higher

(ii)lower

79

--

79

87

--

--

81

1 . 25*10-5

(1. 25*10-5)/81=1. 54*10-7 |[I2]:

C1V1= C2V2

0. 025*20=C2*99

C2=5. 1*10-3 | |

--

252

288

261

--

--

267

1 . 25*10-5

(1. 25*10-5)/267=4. 68*10-8 |[I2]:

C1V1= C2V2

0. 025*5=C2*99

C2=1. 26*10-3 | |B3[H30+]

(i)higher

(ii)lower

91

--

92

94

--

--

92

1 ) 25*10-5

(1. 25*10-5)/92=1. 36*10-7 |[H30+]:

C1V1= C2V2

0. 36*70=C2*99

C2=0. 255 | |

206

226

221

207

--

--

215

1 . 25*10-5

(1. 25*10-5)/215=5. 81*10-8 |[H30+]:

C1V1= C2V2

0. 36*17. 5=C2*99

C2=0. 064 | |B4[S2032-]

(i)lower

(ii)higher

61

67

71

69

--

--

67

six. 25*10-6

(6. 25*10-6)/67=9. 33*10-8 |[S2032-]:...

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